Which Collatz numbers do Busy Beavers simulate (if any)?

For context, Collatz’s Tape is introduced in a post prior for instance. In this one, a small modification is made on top of it.

The following is a comparison between the tape development generated by $n = 371581$ (left - using Collatz’s Tape; to be described in a bit) and $\mathbf{BB(4)}$ (right - using the Turing Machine: 1RB1LB_1LA0LC_1RH1LD_1RD0RA):

The tape on the left is generated in the following manner:

\[f(n) = \begin{cases} n/2 & \text{if} \quad n \equiv 0 \quad (\text{mod}\, 2) \\ (3n + 1)/2 & \text{if} \quad n \equiv 1 \quad (\text{mod}\, 2) \\ \end{cases}\]

flipping the state of the cell it currently stands at (at position $x$) in the following manner:

\[S(x) = \begin{cases} 0 & \text{if} \quad n \equiv 0 \quad (\text{mod}\, 3) \\ 1 - S(x) & \text{if} \quad n \equiv 1 \quad (\text{mod}\, 3) \\ 1 & \text{if} \quad n \equiv 2 \quad (\text{mod}\, 3) \\ \end{cases}\]

Additionally, the reading head moves left if $n$ is odd, and right if $n$ is even. It will do this until $n = 1$ is reached. The tape development can then be seen over time (↓). E.g. $n = 10^{20}$:

Albeit, there are vast differences between the examples shown initially, this comparison was made because it’s known that many Busy Beaver champions (and candidates) display Collatz-like behaviour.


(Un)related interesting Collatz tapes

n CT(n)
$10^{20} + 2$
$10^{20} - 1$
$10^{25}$
$10^{25} - 1$
$10^{70}$

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